Btrfs: convert the inode bit field to use the actual bit operations

Miao pointed this out while I was working on an orphan problem that messing
with a bitfield where different ranges are protected by different locks
doesn't work out right.  Turns out we've been doing this forever where we
have different parts of the bit field protected by either no lock at all or
different locks which could cause all sorts of weird problems including the
issue I was hitting.  So instead make a runtime_flags thing that we use the
normal bit operations on that are all atomic so we can keep having our
no/different locking for the different flags and then make force_compress
it's own thing so it can be treated normally.  Thanks,

Signed-off-by: Josef Bacik <josef@redhat.com>

1 files changed, 2 insertions, 1 deletions

diff --git a/fs/btrfs/disk-io.c b/fs/btrfs/disk-io.c
index 19f5b450f405..0cf8ef2b5b1a 100644
--- a/fs/btrfs/disk-io.c
+++ b/fs/btrfs/disk-io.c
@@ -2001,7 +2001,8 @@ int open_ctree(struct super_block *sb,
         BTRFS_I(fs_info->btree_inode)->root = tree_root;
         memset(&BTRFS_I(fs_info->btree_inode)->location, 0,
                sizeof(struct btrfs_key));
-        BTRFS_I(fs_info->btree_inode)->dummy_inode = 1;
+        set_bit(BTRFS_INODE_DUMMY,
+                &BTRFS_I(fs_info->btree_inode)->runtime_flags);
         insert_inode_hash(fs_info->btree_inode);
 
         spin_lock_init(&fs_info->block_group_cache_lock);