x86, memblock: Add memblock_x86_memory_in_range()

It will return memory size in specified range according to memblock.memory.region

Try to share some code with memblock_x86_free_memory_in_range() by passing get_free to
__memblock_x86_memory_in_range().

-v2: Ben want _in_range in the name instead of size

Signed-off-by: Yinghai Lu <yinghai@kernel.org>
Cc: Benjamin Herrenschmidt <benh@kernel.crashing.org>
Signed-off-by: H. Peter Anvin <hpa@zytor.com>

1 files changed, 1 insertions, 0 deletions

diff --git a/arch/x86/include/asm/memblock.h b/arch/x86/include/asm/memblock.h
index fc3c230812e6..2c304bb6e072 100644
--- a/arch/x86/include/asm/memblock.h
+++ b/arch/x86/include/asm/memblock.h
@@ -16,5 +16,6 @@ void memblock_x86_register_active_regions(int nid, unsigned long start_pfn,
 u64 memblock_x86_hole_size(u64 start, u64 end);
 u64 memblock_x86_find_in_range_node(int nid, u64 start, u64 end, u64 size, u64 align);
 u64 memblock_x86_free_memory_in_range(u64 addr, u64 limit);
+u64 memblock_x86_memory_in_range(u64 addr, u64 limit);
 
 #endif