diff options
author | Linus Torvalds <torvalds@ppc970.osdl.org> | 2005-04-16 18:20:36 -0400 |
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committer | Linus Torvalds <torvalds@ppc970.osdl.org> | 2005-04-16 18:20:36 -0400 |
commit | 1da177e4c3f41524e886b7f1b8a0c1fc7321cac2 (patch) | |
tree | 0bba044c4ce775e45a88a51686b5d9f90697ea9d /arch/ia64/lib/memcpy.S |
Linux-2.6.12-rc2v2.6.12-rc2
Initial git repository build. I'm not bothering with the full history,
even though we have it. We can create a separate "historical" git
archive of that later if we want to, and in the meantime it's about
3.2GB when imported into git - space that would just make the early
git days unnecessarily complicated, when we don't have a lot of good
infrastructure for it.
Let it rip!
Diffstat (limited to 'arch/ia64/lib/memcpy.S')
-rw-r--r-- | arch/ia64/lib/memcpy.S | 301 |
1 files changed, 301 insertions, 0 deletions
diff --git a/arch/ia64/lib/memcpy.S b/arch/ia64/lib/memcpy.S new file mode 100644 index 000000000000..448908d80b69 --- /dev/null +++ b/arch/ia64/lib/memcpy.S | |||
@@ -0,0 +1,301 @@ | |||
1 | /* | ||
2 | * | ||
3 | * Optimized version of the standard memcpy() function | ||
4 | * | ||
5 | * Inputs: | ||
6 | * in0: destination address | ||
7 | * in1: source address | ||
8 | * in2: number of bytes to copy | ||
9 | * Output: | ||
10 | * no return value | ||
11 | * | ||
12 | * Copyright (C) 2000-2001 Hewlett-Packard Co | ||
13 | * Stephane Eranian <eranian@hpl.hp.com> | ||
14 | * David Mosberger-Tang <davidm@hpl.hp.com> | ||
15 | */ | ||
16 | #include <asm/asmmacro.h> | ||
17 | |||
18 | GLOBAL_ENTRY(memcpy) | ||
19 | |||
20 | # define MEM_LAT 21 /* latency to memory */ | ||
21 | |||
22 | # define dst r2 | ||
23 | # define src r3 | ||
24 | # define retval r8 | ||
25 | # define saved_pfs r9 | ||
26 | # define saved_lc r10 | ||
27 | # define saved_pr r11 | ||
28 | # define cnt r16 | ||
29 | # define src2 r17 | ||
30 | # define t0 r18 | ||
31 | # define t1 r19 | ||
32 | # define t2 r20 | ||
33 | # define t3 r21 | ||
34 | # define t4 r22 | ||
35 | # define src_end r23 | ||
36 | |||
37 | # define N (MEM_LAT + 4) | ||
38 | # define Nrot ((N + 7) & ~7) | ||
39 | |||
40 | /* | ||
41 | * First, check if everything (src, dst, len) is a multiple of eight. If | ||
42 | * so, we handle everything with no taken branches (other than the loop | ||
43 | * itself) and a small icache footprint. Otherwise, we jump off to | ||
44 | * the more general copy routine handling arbitrary | ||
45 | * sizes/alignment etc. | ||
46 | */ | ||
47 | .prologue | ||
48 | .save ar.pfs, saved_pfs | ||
49 | alloc saved_pfs=ar.pfs,3,Nrot,0,Nrot | ||
50 | .save ar.lc, saved_lc | ||
51 | mov saved_lc=ar.lc | ||
52 | or t0=in0,in1 | ||
53 | ;; | ||
54 | |||
55 | or t0=t0,in2 | ||
56 | .save pr, saved_pr | ||
57 | mov saved_pr=pr | ||
58 | |||
59 | .body | ||
60 | |||
61 | cmp.eq p6,p0=in2,r0 // zero length? | ||
62 | mov retval=in0 // return dst | ||
63 | (p6) br.ret.spnt.many rp // zero length, return immediately | ||
64 | ;; | ||
65 | |||
66 | mov dst=in0 // copy because of rotation | ||
67 | shr.u cnt=in2,3 // number of 8-byte words to copy | ||
68 | mov pr.rot=1<<16 | ||
69 | ;; | ||
70 | |||
71 | adds cnt=-1,cnt // br.ctop is repeat/until | ||
72 | cmp.gtu p7,p0=16,in2 // copying less than 16 bytes? | ||
73 | mov ar.ec=N | ||
74 | ;; | ||
75 | |||
76 | and t0=0x7,t0 | ||
77 | mov ar.lc=cnt | ||
78 | ;; | ||
79 | cmp.ne p6,p0=t0,r0 | ||
80 | |||
81 | mov src=in1 // copy because of rotation | ||
82 | (p7) br.cond.spnt.few .memcpy_short | ||
83 | (p6) br.cond.spnt.few .memcpy_long | ||
84 | ;; | ||
85 | nop.m 0 | ||
86 | ;; | ||
87 | nop.m 0 | ||
88 | nop.i 0 | ||
89 | ;; | ||
90 | nop.m 0 | ||
91 | ;; | ||
92 | .rotr val[N] | ||
93 | .rotp p[N] | ||
94 | .align 32 | ||
95 | 1: { .mib | ||
96 | (p[0]) ld8 val[0]=[src],8 | ||
97 | nop.i 0 | ||
98 | brp.loop.imp 1b, 2f | ||
99 | } | ||
100 | 2: { .mfb | ||
101 | (p[N-1])st8 [dst]=val[N-1],8 | ||
102 | nop.f 0 | ||
103 | br.ctop.dptk.few 1b | ||
104 | } | ||
105 | ;; | ||
106 | mov ar.lc=saved_lc | ||
107 | mov pr=saved_pr,-1 | ||
108 | mov ar.pfs=saved_pfs | ||
109 | br.ret.sptk.many rp | ||
110 | |||
111 | /* | ||
112 | * Small (<16 bytes) unaligned copying is done via a simple byte-at-the-time | ||
113 | * copy loop. This performs relatively poorly on Itanium, but it doesn't | ||
114 | * get used very often (gcc inlines small copies) and due to atomicity | ||
115 | * issues, we want to avoid read-modify-write of entire words. | ||
116 | */ | ||
117 | .align 32 | ||
118 | .memcpy_short: | ||
119 | adds cnt=-1,in2 // br.ctop is repeat/until | ||
120 | mov ar.ec=MEM_LAT | ||
121 | brp.loop.imp 1f, 2f | ||
122 | ;; | ||
123 | mov ar.lc=cnt | ||
124 | ;; | ||
125 | nop.m 0 | ||
126 | ;; | ||
127 | nop.m 0 | ||
128 | nop.i 0 | ||
129 | ;; | ||
130 | nop.m 0 | ||
131 | ;; | ||
132 | nop.m 0 | ||
133 | ;; | ||
134 | /* | ||
135 | * It is faster to put a stop bit in the loop here because it makes | ||
136 | * the pipeline shorter (and latency is what matters on short copies). | ||
137 | */ | ||
138 | .align 32 | ||
139 | 1: { .mib | ||
140 | (p[0]) ld1 val[0]=[src],1 | ||
141 | nop.i 0 | ||
142 | brp.loop.imp 1b, 2f | ||
143 | } ;; | ||
144 | 2: { .mfb | ||
145 | (p[MEM_LAT-1])st1 [dst]=val[MEM_LAT-1],1 | ||
146 | nop.f 0 | ||
147 | br.ctop.dptk.few 1b | ||
148 | } ;; | ||
149 | mov ar.lc=saved_lc | ||
150 | mov pr=saved_pr,-1 | ||
151 | mov ar.pfs=saved_pfs | ||
152 | br.ret.sptk.many rp | ||
153 | |||
154 | /* | ||
155 | * Large (>= 16 bytes) copying is done in a fancy way. Latency isn't | ||
156 | * an overriding concern here, but throughput is. We first do | ||
157 | * sub-word copying until the destination is aligned, then we check | ||
158 | * if the source is also aligned. If so, we do a simple load/store-loop | ||
159 | * until there are less than 8 bytes left over and then we do the tail, | ||
160 | * by storing the last few bytes using sub-word copying. If the source | ||
161 | * is not aligned, we branch off to the non-congruent loop. | ||
162 | * | ||
163 | * stage: op: | ||
164 | * 0 ld | ||
165 | * : | ||
166 | * MEM_LAT+3 shrp | ||
167 | * MEM_LAT+4 st | ||
168 | * | ||
169 | * On Itanium, the pipeline itself runs without stalls. However, br.ctop | ||
170 | * seems to introduce an unavoidable bubble in the pipeline so the overall | ||
171 | * latency is 2 cycles/iteration. This gives us a _copy_ throughput | ||
172 | * of 4 byte/cycle. Still not bad. | ||
173 | */ | ||
174 | # undef N | ||
175 | # undef Nrot | ||
176 | # define N (MEM_LAT + 5) /* number of stages */ | ||
177 | # define Nrot ((N+1 + 2 + 7) & ~7) /* number of rotating regs */ | ||
178 | |||
179 | #define LOG_LOOP_SIZE 6 | ||
180 | |||
181 | .memcpy_long: | ||
182 | alloc t3=ar.pfs,3,Nrot,0,Nrot // resize register frame | ||
183 | and t0=-8,src // t0 = src & ~7 | ||
184 | and t2=7,src // t2 = src & 7 | ||
185 | ;; | ||
186 | ld8 t0=[t0] // t0 = 1st source word | ||
187 | adds src2=7,src // src2 = (src + 7) | ||
188 | sub t4=r0,dst // t4 = -dst | ||
189 | ;; | ||
190 | and src2=-8,src2 // src2 = (src + 7) & ~7 | ||
191 | shl t2=t2,3 // t2 = 8*(src & 7) | ||
192 | shl t4=t4,3 // t4 = 8*(dst & 7) | ||
193 | ;; | ||
194 | ld8 t1=[src2] // t1 = 1st source word if src is 8-byte aligned, 2nd otherwise | ||
195 | sub t3=64,t2 // t3 = 64-8*(src & 7) | ||
196 | shr.u t0=t0,t2 | ||
197 | ;; | ||
198 | add src_end=src,in2 | ||
199 | shl t1=t1,t3 | ||
200 | mov pr=t4,0x38 // (p5,p4,p3)=(dst & 7) | ||
201 | ;; | ||
202 | or t0=t0,t1 | ||
203 | mov cnt=r0 | ||
204 | adds src_end=-1,src_end | ||
205 | ;; | ||
206 | (p3) st1 [dst]=t0,1 | ||
207 | (p3) shr.u t0=t0,8 | ||
208 | (p3) adds cnt=1,cnt | ||
209 | ;; | ||
210 | (p4) st2 [dst]=t0,2 | ||
211 | (p4) shr.u t0=t0,16 | ||
212 | (p4) adds cnt=2,cnt | ||
213 | ;; | ||
214 | (p5) st4 [dst]=t0,4 | ||
215 | (p5) adds cnt=4,cnt | ||
216 | and src_end=-8,src_end // src_end = last word of source buffer | ||
217 | ;; | ||
218 | |||
219 | // At this point, dst is aligned to 8 bytes and there at least 16-7=9 bytes left to copy: | ||
220 | |||
221 | 1:{ add src=cnt,src // make src point to remainder of source buffer | ||
222 | sub cnt=in2,cnt // cnt = number of bytes left to copy | ||
223 | mov t4=ip | ||
224 | } ;; | ||
225 | and src2=-8,src // align source pointer | ||
226 | adds t4=.memcpy_loops-1b,t4 | ||
227 | mov ar.ec=N | ||
228 | |||
229 | and t0=7,src // t0 = src & 7 | ||
230 | shr.u t2=cnt,3 // t2 = number of 8-byte words left to copy | ||
231 | shl cnt=cnt,3 // move bits 0-2 to 3-5 | ||
232 | ;; | ||
233 | |||
234 | .rotr val[N+1], w[2] | ||
235 | .rotp p[N] | ||
236 | |||
237 | cmp.ne p6,p0=t0,r0 // is src aligned, too? | ||
238 | shl t0=t0,LOG_LOOP_SIZE // t0 = 8*(src & 7) | ||
239 | adds t2=-1,t2 // br.ctop is repeat/until | ||
240 | ;; | ||
241 | add t4=t0,t4 | ||
242 | mov pr=cnt,0x38 // set (p5,p4,p3) to # of bytes last-word bytes to copy | ||
243 | mov ar.lc=t2 | ||
244 | ;; | ||
245 | nop.m 0 | ||
246 | ;; | ||
247 | nop.m 0 | ||
248 | nop.i 0 | ||
249 | ;; | ||
250 | nop.m 0 | ||
251 | ;; | ||
252 | (p6) ld8 val[1]=[src2],8 // prime the pump... | ||
253 | mov b6=t4 | ||
254 | br.sptk.few b6 | ||
255 | ;; | ||
256 | |||
257 | .memcpy_tail: | ||
258 | // At this point, (p5,p4,p3) are set to the number of bytes left to copy (which is | ||
259 | // less than 8) and t0 contains the last few bytes of the src buffer: | ||
260 | (p5) st4 [dst]=t0,4 | ||
261 | (p5) shr.u t0=t0,32 | ||
262 | mov ar.lc=saved_lc | ||
263 | ;; | ||
264 | (p4) st2 [dst]=t0,2 | ||
265 | (p4) shr.u t0=t0,16 | ||
266 | mov ar.pfs=saved_pfs | ||
267 | ;; | ||
268 | (p3) st1 [dst]=t0 | ||
269 | mov pr=saved_pr,-1 | ||
270 | br.ret.sptk.many rp | ||
271 | |||
272 | /////////////////////////////////////////////////////// | ||
273 | .align 64 | ||
274 | |||
275 | #define COPY(shift,index) \ | ||
276 | 1: { .mib \ | ||
277 | (p[0]) ld8 val[0]=[src2],8; \ | ||
278 | (p[MEM_LAT+3]) shrp w[0]=val[MEM_LAT+3],val[MEM_LAT+4-index],shift; \ | ||
279 | brp.loop.imp 1b, 2f \ | ||
280 | }; \ | ||
281 | 2: { .mfb \ | ||
282 | (p[MEM_LAT+4]) st8 [dst]=w[1],8; \ | ||
283 | nop.f 0; \ | ||
284 | br.ctop.dptk.few 1b; \ | ||
285 | }; \ | ||
286 | ;; \ | ||
287 | ld8 val[N-1]=[src_end]; /* load last word (may be same as val[N]) */ \ | ||
288 | ;; \ | ||
289 | shrp t0=val[N-1],val[N-index],shift; \ | ||
290 | br .memcpy_tail | ||
291 | .memcpy_loops: | ||
292 | COPY(0, 1) /* no point special casing this---it doesn't go any faster without shrp */ | ||
293 | COPY(8, 0) | ||
294 | COPY(16, 0) | ||
295 | COPY(24, 0) | ||
296 | COPY(32, 0) | ||
297 | COPY(40, 0) | ||
298 | COPY(48, 0) | ||
299 | COPY(56, 0) | ||
300 | |||
301 | END(memcpy) | ||