[SK_BUFF]: Introduce ipv6_hdr(), remove skb->nh.ipv6h

Now the skb->nh union has just one member, .raw, i.e. it is just like the
skb->mac union, strange, no? I'm just leaving it like that till the transport
layer is done with, when we'll rename skb->mac.raw to skb->mac_header (or
->mac_header_offset?), ditto for ->{h,nh}.

Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>
Signed-off-by: David S. Miller <davem@davemloft.net>

1 files changed, 2 insertions, 2 deletions

diff --git a/net/ipv6/netfilter/ip6t_eui64.c b/net/ipv6/netfilter/ip6t_eui64.c
index c2676066a80..0f3dd932f0a 100644
--- a/net/ipv6/netfilter/ip6t_eui64.c
+++ b/net/ipv6/netfilter/ip6t_eui64.c
@@ -42,7 +42,7 @@ match(const struct sk_buff *skb,
         memset(eui64, 0, sizeof(eui64));
 
         if (eth_hdr(skb)->h_proto == htons(ETH_P_IPV6)) {
-                if (skb->nh.ipv6h->version == 0x6) {
+                if (ipv6_hdr(skb)->version == 0x6) {
                         memcpy(eui64, eth_hdr(skb)->h_source, 3);
                         memcpy(eui64 + 5, eth_hdr(skb)->h_source + 3, 3);
                         eui64[3] = 0xff;
@@ -50,7 +50,7 @@ match(const struct sk_buff *skb,
                         eui64[0] |= 0x02;
 
                         i = 0;
-                        while ((skb->nh.ipv6h->saddr.s6_addr[8+i] == eui64[i])
+                        while ((ipv6_hdr(skb)->saddr.s6_addr[8 + i] == eui64[i])
                                && (i < 8))
                                 i++;