ipv6: correct return on ipv6_rcv() packet drop

The routine ipv6_rcv() uses magic number 0 for a return when it drops a
packet. This corresponds to NET_RX_SUCCESS, which is obviously
incorrect. Correct this by using NET_RX_DROP instead.

ps. It isn't exactly clear who the IPv6 maintainers are, apologies if
I've missed any.

Signed-off-by: Mark Smith <markzzzsmith@yahoo.com.au>
Signed-off-by: David S. Miller <davem@davemloft.net>

1 files changed, 3 insertions, 3 deletions

diff --git a/net/ipv6/ip6_input.c b/net/ipv6/ip6_input.c
index 6d6a4277c67..2d9cbaa67ed 100644
--- a/net/ipv6/ip6_input.c
+++ b/net/ipv6/ip6_input.c
@@ -63,7 +63,7 @@ int ipv6_rcv(struct sk_buff *skb, struct net_device *dev, struct packet_type *pt
 
         if (skb->pkt_type == PACKET_OTHERHOST) {
                 kfree_skb(skb);
-                return 0;
+                return NET_RX_DROP;
         }
 
         rcu_read_lock();
@@ -133,7 +133,7 @@ int ipv6_rcv(struct sk_buff *skb, struct net_device *dev, struct packet_type *pt
                 if (ipv6_parse_hopopts(skb) < 0) {
                         IP6_INC_STATS_BH(net, idev, IPSTATS_MIB_INHDRERRORS);
                         rcu_read_unlock();
-                        return 0;
+                        return NET_RX_DROP;
                 }
         }
 
@@ -149,7 +149,7 @@ err:
 drop:
         rcu_read_unlock();
         kfree_skb(skb);
-        return 0;
+        return NET_RX_DROP;
 }
 
 /*