gpio: present the consumer of a line to userspace

I named the field representing the current user of GPIO line as
"label" but this is too vague and ambiguous. Before anyone gets
confused, rename it to "consumer" and indicate clearly in the
documentation that this is a string set by the user of the line.

Also clean up leftovers in the documentation.

Signed-off-by: Linus Walleij <linus.walleij@linaro.org>

1 files changed, 3 insertions, 3 deletions

diff --git a/tools/gpio/lsgpio.c b/tools/gpio/lsgpio.c
index 6af118cc7efb..1124da375942 100644
--- a/tools/gpio/lsgpio.c
+++ b/tools/gpio/lsgpio.c
@@ -116,10 +116,10 @@ int list_device(const char *device_name)
                         fprintf(stdout, " \"%s\"", linfo.name);
                 else
                         fprintf(stdout, " unnamed");
-                if (linfo.label[0])
-                        fprintf(stdout, " \"%s\"", linfo.label);
+                if (linfo.consumer[0])
+                        fprintf(stdout, " \"%s\"", linfo.consumer);
                 else
-                        fprintf(stdout, " unlabeled");
+                        fprintf(stdout, " unused");
                 if (linfo.flags) {
                         fprintf(stdout, " [");
                         print_flags(linfo.flags);