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-rw-r--r--sound/aoa/codecs/snd-aoa-codec-tas.c13
1 files changed, 9 insertions, 4 deletions
diff --git a/sound/aoa/codecs/snd-aoa-codec-tas.c b/sound/aoa/codecs/snd-aoa-codec-tas.c
index 2ef55a17917c..9de8485ba3f5 100644
--- a/sound/aoa/codecs/snd-aoa-codec-tas.c
+++ b/sound/aoa/codecs/snd-aoa-codec-tas.c
@@ -514,9 +514,15 @@ static int tas_snd_capture_source_put(struct snd_kcontrol *kcontrol,
514 mutex_lock(&tas->mtx); 514 mutex_lock(&tas->mtx);
515 oldacr = tas->acr; 515 oldacr = tas->acr;
516 516
517 tas->acr &= ~TAS_ACR_INPUT_B; 517 /*
518 * Despite what the data sheet says in one place, the
519 * TAS_ACR_B_MONAUREAL bit forces mono output even when
520 * input A (line in) is selected.
521 */
522 tas->acr &= ~(TAS_ACR_INPUT_B | TAS_ACR_B_MONAUREAL);
518 if (ucontrol->value.enumerated.item[0]) 523 if (ucontrol->value.enumerated.item[0])
519 tas->acr |= TAS_ACR_INPUT_B; 524 tas->acr |= TAS_ACR_INPUT_B | TAS_ACR_B_MONAUREAL |
525 TAS_ACR_B_MON_SEL_RIGHT;
520 if (oldacr == tas->acr) { 526 if (oldacr == tas->acr) {
521 mutex_unlock(&tas->mtx); 527 mutex_unlock(&tas->mtx);
522 return 0; 528 return 0;
@@ -686,8 +692,7 @@ static int tas_reset_init(struct tas *tas)
686 if (tas_write_reg(tas, TAS_REG_MCS, 1, &tmp)) 692 if (tas_write_reg(tas, TAS_REG_MCS, 1, &tmp))
687 goto outerr; 693 goto outerr;
688 694
689 tas->acr |= TAS_ACR_ANALOG_PDOWN | TAS_ACR_B_MONAUREAL | 695 tas->acr |= TAS_ACR_ANALOG_PDOWN;
690 TAS_ACR_B_MON_SEL_RIGHT;
691 if (tas_write_reg(tas, TAS_REG_ACR, 1, &tas->acr)) 696 if (tas_write_reg(tas, TAS_REG_ACR, 1, &tas->acr))
692 goto outerr; 697 goto outerr;
693 698