[NET] NETNS: Omit namespace comparision without CONFIG_NET_NS.

Introduce an inline net_eq() to compare two namespaces.
Without CONFIG_NET_NS, since no namespace other than &init_net
exists, it is always 1.

We do not need to convert 1) inline vs inline and
2) inline vs &init_net comparisons.

Signed-off-by: YOSHIFUJI Hideaki <yoshfuji@linux-ipv6.org>

1 files changed, 2 insertions, 2 deletions

diff --git a/net/unix/af_unix.c b/net/unix/af_unix.c
index 4a4793051bcb..50bbf6bb1a22 100644
--- a/net/unix/af_unix.c
+++ b/net/unix/af_unix.c
@@ -252,7 +252,7 @@ static struct sock *__unix_find_socket_byname(struct net *net,
         sk_for_each(s, node, &unix_socket_table[hash ^ type]) {
                 struct unix_sock *u = unix_sk(s);
 
-                if (sock_net(s) != net)
+                if (!net_eq(sock_net(s), net))
                         continue;
 
                 if (u->addr->len == len &&
@@ -289,7 +289,7 @@ static struct sock *unix_find_socket_byinode(struct net *net, struct inode *i)
                     &unix_socket_table[i->i_ino & (UNIX_HASH_SIZE - 1)]) {
                 struct dentry *dentry = unix_sk(s)->dentry;
 
-                if (sock_net(s) != net)
+                if (!net_eq(sock_net(s), net))
                         continue;
 
                 if(dentry && dentry->d_inode == i)