[NET] NETNS: Omit namespace comparision without CONFIG_NET_NS.

Introduce an inline net_eq() to compare two namespaces.
Without CONFIG_NET_NS, since no namespace other than &init_net
exists, it is always 1.

We do not need to convert 1) inline vs inline and
2) inline vs &init_net comparisons.

Signed-off-by: YOSHIFUJI Hideaki <yoshfuji@linux-ipv6.org>

1 files changed, 1 insertions, 1 deletions

diff --git a/net/ipv6/inet6_hashtables.c b/net/ipv6/inet6_hashtables.c
index 21c467675412..340c7d42b83a 100644
--- a/net/ipv6/inet6_hashtables.c
+++ b/net/ipv6/inet6_hashtables.c
@@ -105,7 +105,7 @@ struct sock *inet6_lookup_listener(struct net *net,
 
         read_lock(&hashinfo->lhash_lock);
         sk_for_each(sk, node, &hashinfo->listening_hash[inet_lhashfn(hnum)]) {
-                if (sock_net(sk) == net && inet_sk(sk)->num == hnum &&
+                if (net_eq(sock_net(sk), net) && inet_sk(sk)->num == hnum &&
                                 sk->sk_family == PF_INET6) {
                         const struct ipv6_pinfo *np = inet6_sk(sk);