[NET] NETNS: Omit namespace comparision without CONFIG_NET_NS.

Introduce an inline net_eq() to compare two namespaces.
Without CONFIG_NET_NS, since no namespace other than &init_net
exists, it is always 1.

We do not need to convert 1) inline vs inline and
2) inline vs &init_net comparisons.

Signed-off-by: YOSHIFUJI Hideaki <yoshfuji@linux-ipv6.org>

1 files changed, 1 insertions, 1 deletions

diff --git a/net/ipv4/raw.c b/net/ipv4/raw.c
index 25dc8b38cac3..d965f0a39c84 100644
--- a/net/ipv4/raw.c
+++ b/net/ipv4/raw.c
@@ -117,7 +117,7 @@ static struct sock *__raw_v4_lookup(struct net *net, struct sock *sk,
         sk_for_each_from(sk, node) {
                 struct inet_sock *inet = inet_sk(sk);
 
-                if (sock_net(sk) == net && inet->num == num             &&
+                if (net_eq(sock_net(sk), net) && inet->num == num       &&
                     !(inet->daddr && inet->daddr != raddr)              &&
                     !(inet->rcv_saddr && inet->rcv_saddr != laddr)      &&
                     !(sk->sk_bound_dev_if && sk->sk_bound_dev_if != dif))