slub: do not fail if we cannot register a slab with sysfs

Do not BUG() if we cannot register a slab with sysfs.  Just print an error.
 The only consequence of not registering is that the slab cache is not
visible via /sys/slab.  A BUG() may not be visible that early during boot
and we have had multiple issues here already.

Signed-off-by: Christoph Lameter <clameter@sgi.com>
Acked-by: David S. Miller <davem@davemloft.net>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

1 files changed, 6 insertions, 2 deletions

diff --git a/mm/slub.c b/mm/slub.c
index 04151da399c6..7defe84e6bd0 100644
--- a/mm/slub.c
+++ b/mm/slub.c
@@ -3813,7 +3813,9 @@ static int __init slab_sysfs_init(void)
 
         list_for_each_entry(s, &slab_caches, list) {
                 err = sysfs_slab_add(s);
-                BUG_ON(err);
+                if (err)
+                        printk(KERN_ERR "SLUB: Unable to add boot slab %s"
+                                                " to sysfs\n", s->name);
         }
 
         while (alias_list) {
@@ -3821,7 +3823,9 @@ static int __init slab_sysfs_init(void)
 
                 alias_list = alias_list->next;
                 err = sysfs_slab_alias(al->s, al->name);
-                BUG_ON(err);
+                if (err)
+                        printk(KERN_ERR "SLUB: Unable to add boot slab alias"
+                                        " %s to sysfs\n", s->name);
                 kfree(al);
         }