sched: Remove member rt_se from struct rt_rq

It's a duplicate of tg->rt_se[cpu] and the only usage is
sched_rt_rq_dequeue() and sched_rt_rq_enqueue(). After the
first patch to those two function. rt_se can be removed.

Signed-off-by: Yong Zhang <yong.zhang0@gmail.com>
Cc: Rusty Russell <rusty@rustcorp.com.au>
Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
LKML-Reference: <2674af741001282258q38781619u653ca4a7dd267347@mail.gmail.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>

1 files changed, 0 insertions, 2 deletions

diff --git a/kernel/sched.c b/kernel/sched.c
index 2386f5440002..6cee227b1459 100644
--- a/kernel/sched.c
+++ b/kernel/sched.c
@@ -436,7 +436,6 @@ struct rt_rq {
         struct rq *rq;
         struct list_head leaf_rt_rq_list;
         struct task_group *tg;
-        struct sched_rt_entity *rt_se;
 #endif
 };
 
@@ -7592,7 +7591,6 @@ static void init_tg_rt_entry(struct task_group *tg, struct rt_rq *rt_rq,
         tg->rt_rq[cpu] = rt_rq;
         init_rt_rq(rt_rq, rq);
         rt_rq->tg = tg;
-        rt_rq->rt_se = rt_se;
         rt_rq->rt_runtime = tg->rt_bandwidth.rt_runtime;
         if (add)
                 list_add(&rt_rq->leaf_rt_rq_list, &rq->leaf_rt_rq_list);