sched: Change usage of rt_rq->rt_se to rt_rq->tg->rt_se[cpu]

This is the first step to remove rt_rq member rt_se because it have the
same meaning with tg->rt_se[cpu]. And the latter style is also used by
the fair scheduling class.

Signed-off-by: Yong Zhang <yong.zhang0@gmail.com>
Cc: Rusty Russell <rusty@rustcorp.com.au>
Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
LKML-Reference: <2674af741001282257r28c97a92o9f90cf16fe8d3d84@mail.gmail.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>

1 files changed, 8 insertions, 2 deletions

diff --git a/kernel/sched_rt.c b/kernel/sched_rt.c
index ca49ceb01201..bf3e38fdbe6d 100644
--- a/kernel/sched_rt.c
+++ b/kernel/sched_rt.c
@@ -199,8 +199,11 @@ static void dequeue_rt_entity(struct sched_rt_entity *rt_se);
 
 static void sched_rt_rq_enqueue(struct rt_rq *rt_rq)
 {
+        int this_cpu = smp_processor_id();
         struct task_struct *curr = rq_of_rt_rq(rt_rq)->curr;
-        struct sched_rt_entity *rt_se = rt_rq->rt_se;
+        struct sched_rt_entity *rt_se;
+
+        rt_se = rt_rq->tg->rt_se[this_cpu];
 
         if (rt_rq->rt_nr_running) {
                 if (rt_se && !on_rt_rq(rt_se))
@@ -212,7 +215,10 @@ static void sched_rt_rq_enqueue(struct rt_rq *rt_rq)
 
 static void sched_rt_rq_dequeue(struct rt_rq *rt_rq)
 {
-        struct sched_rt_entity *rt_se = rt_rq->rt_se;
+        int this_cpu = smp_processor_id();
+        struct sched_rt_entity *rt_se;
+
+        rt_se = rt_rq->tg->rt_se[this_cpu];
 
         if (rt_se && on_rt_rq(rt_se))
                 dequeue_rt_entity(rt_se);