slub: Do not use 192 byte sized cache if minimum alignment is 128 byte

The 192 byte cache is not necessary if we have a basic alignment of 128
byte. If it would be used then the 192 would be aligned to the next 128 byte
boundary which would result in another 256 byte cache. Two 256 kmalloc caches
cause sysfs to complain about a duplicate entry.

MIPS needs 128 byte aligned kmalloc caches and spits out warnings on boot without
this patch.

Signed-off-by: Christoph Lameter <cl@linux-foundation.org>
Signed-off-by: Pekka Enberg <penberg@cs.helsinki.fi>

1 files changed, 2 insertions, 0 deletions

diff --git a/include/linux/slub_def.h b/include/linux/slub_def.h
index 71e43a12ebbb..cef6f8fddd7d 100644
--- a/include/linux/slub_def.h
+++ b/include/linux/slub_def.h
@@ -137,10 +137,12 @@ static __always_inline int kmalloc_index(size_t size)
         if (size <= KMALLOC_MIN_SIZE)
                 return KMALLOC_SHIFT_LOW;
 
+#if KMALLOC_MIN_SIZE <= 64
         if (size > 64 && size <= 96)
                 return 1;
         if (size > 128 && size <= 192)
                 return 2;
+#endif
         if (size <=          8) return 3;
         if (size <=         16) return 4;
         if (size <=         32) return 5;