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authorZachary Amsden <zach@vmware.com>2005-08-16 15:05:09 -0400
committerLinus Torvalds <torvalds@g5.osdl.org>2005-08-16 15:18:01 -0400
commit12aaa0855b39b5464db953fedf399fa91ee365ed (patch)
treed202ce6d6529fe23e950e24cd04b4d562f28705e /include
parent5153f7e6dba37390902c8fd3edc9a8cc19358ece (diff)
[PATCH] i386 / desc_empty macro is incorrect
Chuck Ebbert noticed that the desc_empty macro is incorrect. Fix it. Thankfully, this is not used as a security check, but it can falsely overwrite TLS segments with carefully chosen base / limits. I do not believe this is an issue in practice, but it is a kernel bug. Signed-off-by: Zachary Amsden <zach@vmware.com> Signed-off-by: Chris Wright <chrisw@osdl.org> [ x86-64 had the same problem, and the same fix. Linus ] Signed-off-by: Linus Torvalds <torvalds@osdl.org>
Diffstat (limited to 'include')
-rw-r--r--include/asm-i386/processor.h2
-rw-r--r--include/asm-x86_64/processor.h2
2 files changed, 2 insertions, 2 deletions
diff --git a/include/asm-i386/processor.h b/include/asm-i386/processor.h
index 5d06e6bd6ba0..d0d8b0160090 100644
--- a/include/asm-i386/processor.h
+++ b/include/asm-i386/processor.h
@@ -29,7 +29,7 @@ struct desc_struct {
29}; 29};
30 30
31#define desc_empty(desc) \ 31#define desc_empty(desc) \
32 (!((desc)->a + (desc)->b)) 32 (!((desc)->a | (desc)->b))
33 33
34#define desc_equal(desc1, desc2) \ 34#define desc_equal(desc1, desc2) \
35 (((desc1)->a == (desc2)->a) && ((desc1)->b == (desc2)->b)) 35 (((desc1)->a == (desc2)->a) && ((desc1)->b == (desc2)->b))
diff --git a/include/asm-x86_64/processor.h b/include/asm-x86_64/processor.h
index 106f666517bb..85549e656eeb 100644
--- a/include/asm-x86_64/processor.h
+++ b/include/asm-x86_64/processor.h
@@ -32,7 +32,7 @@
32#define ID_MASK 0x00200000 32#define ID_MASK 0x00200000
33 33
34#define desc_empty(desc) \ 34#define desc_empty(desc) \
35 (!((desc)->a + (desc)->b)) 35 (!((desc)->a | (desc)->b))
36 36
37#define desc_equal(desc1, desc2) \ 37#define desc_equal(desc1, desc2) \
38 (((desc1)->a == (desc2)->a) && ((desc1)->b == (desc2)->b)) 38 (((desc1)->a == (desc2)->a) && ((desc1)->b == (desc2)->b))