get_task_comm(): return the result

It was dumb to make get_task_comm() return void.  Change it to return a
pointer to the resulting output for caller convenience.

Cc: Ulrich Drepper <drepper@redhat.com>
Cc: Ingo Molnar <mingo@elte.hu>
Cc: Roland McGrath <roland@redhat.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

1 files changed, 1 insertions, 1 deletions

diff --git a/include/linux/sched.h b/include/linux/sched.h
index af6947e69b40..680bb03a4b90 100644
--- a/include/linux/sched.h
+++ b/include/linux/sched.h
@@ -1770,7 +1770,7 @@ extern long do_fork(unsigned long, unsigned long, struct pt_regs *, unsigned lon
 struct task_struct *fork_idle(int);
 
 extern void set_task_comm(struct task_struct *tsk, char *from);
-extern void get_task_comm(char *to, struct task_struct *tsk);
+extern char *get_task_comm(char *to, struct task_struct *tsk);
 
 #ifdef CONFIG_SMP
 extern void wait_task_inactive(struct task_struct * p);