UBIFS: fix recovery broken by the previous recovery fix

Unfortunately, the recovery fix d1606a59b6be4ea392eabd40d1250aa1eeb19efb
(UBIFS: fix extremely rare mount failure) broke recovery. This commit make
UBIFS drop the last min. I/O unit in all journal heads, but this is needed only
for the GC head. And this does not work for non-GC heads. For example, if
suppose we have min. I/O units A and B, and A contains a valid node X, which
was fsynced, and then a group of nodes Y which spans the rest of A and B. In
this case we'll drop not only Y, but also X, which is obviously incorrect.

This patch fixes the issue and additionally makes recovery to drop last min.
I/O unit only for the GC head, and leave things as they have been for ages for
the other heads - this is safer.

Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>

1 files changed, 87 insertions, 65 deletions

diff --git a/fs/ubifs/recovery.c b/fs/ubifs/recovery.c
index 6adb5328a016..783d8e0beb76 100644
--- a/fs/ubifs/recovery.c
+++ b/fs/ubifs/recovery.c
@@ -564,19 +564,15 @@ static int fix_unclean_leb(struct ubifs_info *c, struct ubifs_scan_leb *sleb,
 }
 
 /**
- * drop_last_node - drop the last node or group of nodes.
+ * drop_last_group - drop the last group of nodes.
  * @sleb: scanned LEB information
  * @offs: offset of dropped nodes is returned here
- * @grouped: non-zero if whole group of nodes have to be dropped
  *
  * This is a helper function for 'ubifs_recover_leb()' which drops the last
- * node of the scanned LEB or the last group of nodes if @grouped is not zero.
- * This function returns %1 if a node was dropped and %0 otherwise.
+ * group of nodes of the scanned LEB.
  */
-static int drop_last_node(struct ubifs_scan_leb *sleb, int *offs, int grouped)
+static void drop_last_group(struct ubifs_scan_leb *sleb, int *offs)
 {
-        int dropped = 0;
-
         while (!list_empty(&sleb->nodes)) {
                 struct ubifs_scan_node *snod;
                 struct ubifs_ch *ch;
@@ -585,17 +581,40 @@ static int drop_last_node(struct ubifs_scan_leb *sleb, int *offs, int grouped)
                                   list);
                 ch = snod->node;
                 if (ch->group_type != UBIFS_IN_NODE_GROUP)
-                        return dropped;
-                dbg_rcvry("dropping node at %d:%d", sleb->lnum, snod->offs);
+                        break;
+
+                dbg_rcvry("dropping grouped node at %d:%d",
+                          sleb->lnum, snod->offs);
+                *offs = snod->offs;
+                list_del(&snod->list);
+                kfree(snod);
+                sleb->nodes_cnt -= 1;
+        }
+}
+
+/**
+ * drop_last_node - drop the last node.
+ * @sleb: scanned LEB information
+ * @offs: offset of dropped nodes is returned here
+ * @grouped: non-zero if whole group of nodes have to be dropped
+ *
+ * This is a helper function for 'ubifs_recover_leb()' which drops the last
+ * node of the scanned LEB.
+ */
+static void drop_last_node(struct ubifs_scan_leb *sleb, int *offs)
+{
+        struct ubifs_scan_node *snod;
+
+        if (!list_empty(&sleb->nodes)) {
+                snod = list_entry(sleb->nodes.prev, struct ubifs_scan_node,
+                                  list);
+
+                dbg_rcvry("dropping last node at %d:%d", sleb->lnum, snod->offs);
                 *offs = snod->offs;
                 list_del(&snod->list);
                 kfree(snod);
                 sleb->nodes_cnt -= 1;
-                dropped = 1;
-                if (!grouped)
-                        break;
         }
-        return dropped;
 }
 
 /**
@@ -697,59 +716,62 @@ struct ubifs_scan_leb *ubifs_recover_leb(struct ubifs_info *c, int lnum,
                  * If nodes are grouped, always drop the incomplete group at
                  * the end.
                  */
-                drop_last_node(sleb, &offs, 1);
+                drop_last_group(sleb, &offs);
 
-        /*
-         * While we are in the middle of the same min. I/O unit keep dropping
-         * nodes. So basically, what we want is to make sure that the last min.
-         * I/O unit where we saw the corruption is dropped completely with all
-         * the uncorrupted nodes which may possibly sit there.
-         *
-         * In other words, let's name the min. I/O unit where the corruption
-         * starts B, and the previous min. I/O unit A. The below code tries to
-         * deal with a situation when half of B contains valid nodes or the end
-         * of a valid node, and the second half of B contains corrupted data or
-         * garbage. This means that UBIFS had been writing to B just before the
-         * power cut happened. I do not know how realistic is this scenario
-         * that half of the min. I/O unit had been written successfully and the
-         * other half not, but this is possible in our 'failure mode emulation'
-         * infrastructure at least.
-         *
-         * So what is the problem, why we need to drop those nodes? Whey can't
-         * we just clean-up the second half of B by putting a padding node
-         * there? We can, and this works fine with one exception which was
-         * reproduced with power cut emulation testing and happens extremely
-         * rarely. The description follows, but it is worth noting that that is
-         * only about the GC head, so we could do this trick only if the bud
-         * belongs to the GC head, but it does not seem to be worth an
-         * additional "if" statement.
-         *
-         * So, imagine the file-system is full, we run GC which is moving valid
-         * nodes from LEB X to LEB Y (obviously, LEB Y is the current GC head
-         * LEB). The @c->gc_lnum is -1, which means that GC will retain LEB X
-         * and will try to continue. Imagine that LEB X is currently the
-         * dirtiest LEB, and the amount of used space in LEB Y is exactly the
-         * same as amount of free space in LEB X.
-         *
-         * And a power cut happens when nodes are moved from LEB X to LEB Y. We
-         * are here trying to recover LEB Y which is the GC head LEB. We find
-         * the min. I/O unit B as described above. Then we clean-up LEB Y by
-         * padding min. I/O unit. And later 'ubifs_rcvry_gc_commit()' function
-         * fails, because it cannot find a dirty LEB which could be GC'd into
-         * LEB Y! Even LEB X does not match because the amount of valid nodes
-         * there does not fit the free space in LEB Y any more! And this is
-         * because of the padding node which we added to LEB Y. The
-         * user-visible effect of this which I once observed and analysed is
-         * that we cannot mount the file-system with -ENOSPC error.
-         *
-         * So obviously, to make sure that situation does not happen we should
-         * free min. I/O unit B in LEB Y completely and the last used min. I/O
-         * unit in LEB Y should be A. This is basically what the below code
-         * tries to do.
-         */
-        while (min_io_unit == round_down(offs, c->min_io_size) &&
-               min_io_unit != offs &&
-               drop_last_node(sleb, &offs, grouped));
+        if (jhead == GCHD) {
+                /*
+                 * If this LEB belongs to the GC head then while we are in the
+                 * middle of the same min. I/O unit keep dropping nodes. So
+                 * basically, what we want is to make sure that the last min.
+                 * I/O unit where we saw the corruption is dropped completely
+                 * with all the uncorrupted nodes which may possibly sit there.
+                 *
+                 * In other words, let's name the min. I/O unit where the
+                 * corruption starts B, and the previous min. I/O unit A. The
+                 * below code tries to deal with a situation when half of B
+                 * contains valid nodes or the end of a valid node, and the
+                 * second half of B contains corrupted data or garbage. This
+                 * means that UBIFS had been writing to B just before the power
+                 * cut happened. I do not know how realistic is this scenario
+                 * that half of the min. I/O unit had been written successfully
+                 * and the other half not, but this is possible in our 'failure
+                 * mode emulation' infrastructure at least.
+                 *
+                 * So what is the problem, why we need to drop those nodes? Why
+                 * can't we just clean-up the second half of B by putting a
+                 * padding node there? We can, and this works fine with one
+                 * exception which was reproduced with power cut emulation
+                 * testing and happens extremely rarely.
+                 *
+                 * Imagine the file-system is full, we run GC which starts
+                 * moving valid nodes from LEB X to LEB Y (obviously, LEB Y is
+                 * the current GC head LEB). The @c->gc_lnum is -1, which means
+                 * that GC will retain LEB X and will try to continue. Imagine
+                 * that LEB X is currently the dirtiest LEB, and the amount of
+                 * used space in LEB Y is exactly the same as amount of free
+                 * space in LEB X.
+                 *
+                 * And a power cut happens when nodes are moved from LEB X to
+                 * LEB Y. We are here trying to recover LEB Y which is the GC
+                 * head LEB. We find the min. I/O unit B as described above.
+                 * Then we clean-up LEB Y by padding min. I/O unit. And later
+                 * 'ubifs_rcvry_gc_commit()' function fails, because it cannot
+                 * find a dirty LEB which could be GC'd into LEB Y! Even LEB X
+                 * does not match because the amount of valid nodes there does
+                 * not fit the free space in LEB Y any more! And this is
+                 * because of the padding node which we added to LEB Y. The
+                 * user-visible effect of this which I once observed and
+                 * analysed is that we cannot mount the file-system with
+                 * -ENOSPC error.
+                 *
+                 * So obviously, to make sure that situation does not happen we
+                 * should free min. I/O unit B in LEB Y completely and the last
+                 * used min. I/O unit in LEB Y should be A. This is basically
+                 * what the below code tries to do.
+                 */
+                while (offs > min_io_unit)
+                        drop_last_node(sleb, &offs);
+        }
 
         buf = sbuf + offs;
         len = c->leb_size - offs;