UBIFS: remove dead code

UBIFS assumes that @c->min_io_size is 8 in case of NOR flash. This
is because UBIFS alignes all nodes to 8-byte boundary, and maintaining
@c->min_io_size introduced unnecessary complications.

This patch removes senseless constructs like:

if (c->min_io_size == 1)
	NOR-specific code

Also, few commentaries amendments.

Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>

1 files changed, 4 insertions, 27 deletions

diff --git a/fs/ubifs/recovery.c b/fs/ubifs/recovery.c
index 10662975d2ef..805605250f12 100644
--- a/fs/ubifs/recovery.c
+++ b/fs/ubifs/recovery.c
@@ -343,33 +343,15 @@ int ubifs_write_rcvrd_mst_node(struct ubifs_info *c)
  *
  * This function returns %1 if @offs was in the last write to the LEB whose data
  * is in @buf, otherwise %0 is returned.  The determination is made by checking
- * for subsequent empty space starting from the next min_io_size boundary (or a
- * bit less than the common header size if min_io_size is one).
+ * for subsequent empty space starting from the next @c->min_io_size boundary.
  */
 static int is_last_write(const struct ubifs_info *c, void *buf, int offs)
 {
-        int empty_offs;
-        int check_len;
+        int empty_offs, check_len;
         uint8_t *p;
 
-        if (c->min_io_size == 1) {
-                check_len = c->leb_size - offs;
-                p = buf + check_len;
-                for (; check_len > 0; check_len--)
-                        if (*--p != 0xff)
-                                break;
-                /*
-                 * 'check_len' is the size of the corruption which cannot be
-                 * more than the size of 1 node if it was caused by an unclean
-                 * unmount.
-                 */
-                if (check_len > UBIFS_MAX_NODE_SZ)
-                        return 0;
-                return 1;
-        }
-
         /*
-         * Round up to the next c->min_io_size boundary i.e. 'offs' is in the
+         * Round up to the next @c->min_io_size boundary i.e. @offs is in the
          * last wbuf written. After that should be empty space.
          */
         empty_offs = ALIGN(offs + 1, c->min_io_size);
@@ -392,7 +374,7 @@ static int is_last_write(const struct ubifs_info *c, void *buf, int offs)
  *
  * This function pads up to the next min_io_size boundary (if there is one) and
  * sets empty space to all 0xff. @buf, @offs and @len are updated to the next
- * min_io_size boundary (if there is one).
+ * @c->min_io_size boundary.
  */
 static void clean_buf(const struct ubifs_info *c, void **buf, int lnum,
                       int *offs, int *len)
@@ -402,11 +384,6 @@ static void clean_buf(const struct ubifs_info *c, void **buf, int lnum,
         lnum = lnum;
         dbg_rcvry("cleaning corruption at %d:%d", lnum, *offs);
 
-        if (c->min_io_size == 1) {
-                memset(*buf, 0xff, c->leb_size - *offs);
-                return;
-        }
-
         ubifs_assert(!(*offs & 7));
         empty_offs = ALIGN(*offs, c->min_io_size);
         pad_len = empty_offs - *offs;