d_path: Make seq_path() use a struct path argument

seq_path() is always called with a dentry and a vfsmount from a struct path.
Make seq_path() take it directly as an argument.

Signed-off-by: Jan Blunck <jblunck@suse.de>
Cc: Christoph Hellwig <hch@lst.de>
Cc: Al Viro <viro@zeniv.linux.org.uk>
Cc: "J. Bruce Fields" <bfields@fieldses.org>
Cc: Neil Brown <neilb@suse.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

1 files changed, 3 insertions, 4 deletions

diff --git a/fs/seq_file.c b/fs/seq_file.c
index ca71c115bdaa..8d862907f060 100644
--- a/fs/seq_file.c
+++ b/fs/seq_file.c
@@ -342,13 +342,12 @@ int seq_printf(struct seq_file *m, const char *f, ...)
 }
 EXPORT_SYMBOL(seq_printf);
 
-int seq_path(struct seq_file *m,
-             struct vfsmount *mnt, struct dentry *dentry,
-             char *esc)
+int seq_path(struct seq_file *m, struct path *path, char *esc)
 {
         if (m->count < m->size) {
                 char *s = m->buf + m->count;
-                char *p = d_path(dentry, mnt, s, m->size - m->count);
+                char *p = d_path(path->dentry, path->mnt, s,
+                                 m->size - m->count);
                 if (!IS_ERR(p)) {
                         while (s <= p) {
                                 char c = *p++;