ext4: delayed allocation i_blocks fix for stat

Right now i_blocks is not getting updated until the blocks are actually
allocaed on disk.  This means with delayed allocation, right after files
are copied, "ls -sF" shoes the file as taking 0 blocks on disk.  "du"
also shows the files taking zero space, which is highly confusing to the
user.

Since delayed allocation already keeps track of per-inode total
number of blocks that are subject to delayed allocation, this patch fix
this by using that to adjust the value returned by stat(2). When real
block allocation is done, the i_blocks will get updated. Since the
reserved blocks for delayed allocation will be decreased, this will be
keep value returned by stat(2) consistent.

Signed-off-by: Mingming Cao <cmm@us.ibm.com>
Signed-off-by: "Theodore Ts'o" <tytso@mit.edu>

1 files changed, 2 insertions, 0 deletions

diff --git a/fs/ext4/ext4.h b/fs/ext4/ext4.h
index 0962f4e26579..303e41cf7b14 100644
--- a/fs/ext4/ext4.h
+++ b/fs/ext4/ext4.h
@@ -1059,6 +1059,8 @@ int ext4_get_blocks_handle(handle_t *handle, struct inode *inode,
 extern struct inode *ext4_iget(struct super_block *, unsigned long);
 extern int  ext4_write_inode (struct inode *, int);
 extern int  ext4_setattr (struct dentry *, struct iattr *);
+extern int  ext4_getattr(struct vfsmount *mnt, struct dentry *dentry,
+                                struct kstat *stat);
 extern void ext4_delete_inode (struct inode *);
 extern int  ext4_sync_inode (handle_t *, struct inode *);
 extern void ext4_discard_reservation (struct inode *);