gpu: host1x: Call ->remove() only when a device is bound

When a driver's ->probe() function fails, the host1x bus must not call
its ->remove() function because the driver will already have cleaned up
in the error handling path in ->probe().

Signed-off-by: Thierry Reding <treding@nvidia.com>

1 files changed, 7 insertions, 2 deletions

diff --git a/drivers/gpu/host1x/bus.c b/drivers/gpu/host1x/bus.c
index aaf54859adb0..e4182e68e29c 100644
--- a/drivers/gpu/host1x/bus.c
+++ b/drivers/gpu/host1x/bus.c
@@ -116,7 +116,10 @@ static void host1x_subdev_register(struct host1x_device *device,
         if (list_empty(&device->subdevs)) {
                 err = device->driver->probe(device);
                 if (err < 0)
-                        dev_err(&device->dev, "probe failed: %d\n", err);
+                        dev_err(&device->dev, "probe failed for %ps: %d\n",
+                                device->driver, err);
+                else
+                        device->bound = true;
         }
 }
 
@@ -130,10 +133,12 @@ static void __host1x_subdev_unregister(struct host1x_device *device,
          * If all subdevices have been activated, we're about to remove the
          * first active subdevice, so unload the driver first.
          */
-        if (list_empty(&device->subdevs)) {
+        if (list_empty(&device->subdevs) && device->bound) {
                 err = device->driver->remove(device);
                 if (err < 0)
                         dev_err(&device->dev, "remove failed: %d\n", err);
+
+                device->bound = false;
         }
 
         /*