[CPUFREQ] Disambiguate loop indexes in powernow-k7

This shouldn't have actually caused any problems
(as we return if we 'corrupt' 'i', but it's still not
very pretty.  For the sake of adding another local variable,
this got cleaner.

Signed-off-by: Dave Jones <davej@redhat.com>

1 files changed, 4 insertions, 4 deletions

diff --git a/arch/i386/kernel/cpu/cpufreq/powernow-k7.c b/arch/i386/kernel/cpu/cpufreq/powernow-k7.c
index 2bf4237cb94e..5d2b601425b8 100644
--- a/arch/i386/kernel/cpu/cpufreq/powernow-k7.c
+++ b/arch/i386/kernel/cpu/cpufreq/powernow-k7.c
@@ -452,23 +452,23 @@ static int powernow_decode_bios (int maxfid, int startvid)
 
                         pst = (struct pst_s *) p;
 
-                        for (i = 0 ; i <psb->numpst; i++) {
+                        for (j=0; j<psb->numpst; j++) {
                                 pst = (struct pst_s *) p;
                                 number_scales = pst->numpstates;
 
                                 if ((etuple == pst->cpuid) && check_fsb(pst->fsbspeed) &&
                                     (maxfid==pst->maxfid) && (startvid==pst->startvid))
                                 {
-                                        dprintk ("PST:%d (@%p)\n", i, pst);
+                                        dprintk ("PST:%d (@%p)\n", j, pst);
                                         dprintk (" cpuid: 0x%x  fsb: %d  maxFID: 0x%x  startvid: 0x%x\n",
                                                  pst->cpuid, pst->fsbspeed, pst->maxfid, pst->startvid);
 
                                         ret = get_ranges ((char *) pst + sizeof (struct pst_s));
                                         return ret;
-
                                 } else {
+                                        unsigned int k;
                                         p = (char *) pst + sizeof (struct pst_s);
-                                        for (j=0 ; j < number_scales; j++)
+                                        for (k=0; k<number_scales; k++)
                                                 p+=2;
                                 }
                         }