x86: Avoid double stack traces with show_regs()

What was called show_registers() so far already showed a stack
trace for kernel faults, and kernel_stack_pointer() isn't even
valid to be used for faults from user mode, hence it was
pointless for show_regs() to call show_trace() after
show_registers().

Simply rename show_registers() to show_regs() and eliminate
the old definition.

Signed-off-by: Jan Beulich <jbeulich@suse.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Andrew Morton <akpm@linux-foundation.org>
Cc: Arjan van de Ven <arjan@linux.intel.com>
Cc: Frederic Weisbecker <fweisbec@gmail.com>
Link: http://lkml.kernel.org/r/4FAA3D3902000078000826E1@nat28.tlf.novell.com
Signed-off-by: Ingo Molnar <mingo@kernel.org>

1 files changed, 1 insertions, 1 deletions

diff --git a/arch/x86/kernel/dumpstack.c b/arch/x86/kernel/dumpstack.c
index 1b81839b6c88..40989da4bb22 100644
--- a/arch/x86/kernel/dumpstack.c
+++ b/arch/x86/kernel/dumpstack.c
@@ -271,7 +271,7 @@ int __kprobes __die(const char *str, struct pt_regs *regs, long err)
                         current->thread.trap_nr, SIGSEGV) == NOTIFY_STOP)
                 return 1;
 
-        show_registers(regs);
+        show_regs(regs);
 #ifdef CONFIG_X86_32
         if (user_mode_vm(regs)) {
                 sp = regs->sp;