Linux-2.6.12-rc2v2.6.12-rc2

Initial git repository build. I'm not bothering with the full history,
even though we have it. We can create a separate "historical" git
archive of that later if we want to, and in the meantime it's about
3.2GB when imported into git - space that would just make the early
git days unnecessarily complicated, when we don't have a lot of good
infrastructure for it.

Let it rip!

1 files changed, 382 insertions, 0 deletions

diff --git a/arch/sparc/lib/rem.S b/arch/sparc/lib/rem.S
new file mode 100644
index 000000000000..44508148d055
--- /dev/null
+++ b/arch/sparc/lib/rem.S
@@ -0,0 +1,382 @@
+/* $Id: rem.S,v 1.7 1996/09/30 02:22:34 davem Exp $
+ * rem.S:       This routine was taken from glibc-1.09 and is covered
+ *              by the GNU Library General Public License Version 2.
+ */
+
+
+/* This file is generated from divrem.m4; DO NOT EDIT! */
+/*
+ * Division and remainder, from Appendix E of the Sparc Version 8
+ * Architecture Manual, with fixes from Gordon Irlam.
+ */
+
+/*
+ * Input: dividend and divisor in %o0 and %o1 respectively.
+ *
+ * m4 parameters:
+ *  .rem        name of function to generate
+ *  rem         rem=div => %o0 / %o1; rem=rem => %o0 % %o1
+ *  true                true=true => signed; true=false => unsigned
+ *
+ * Algorithm parameters:
+ *  N           how many bits per iteration we try to get (4)
+ *  WORDSIZE    total number of bits (32)
+ *
+ * Derived constants:
+ *  TOPBITS     number of bits in the top decade of a number
+ *
+ * Important variables:
+ *  Q           the partial quotient under development (initially 0)
+ *  R           the remainder so far, initially the dividend
+ *  ITER        number of main division loop iterations required;
+ *              equal to ceil(log2(quotient) / N).  Note that this
+ *              is the log base (2^N) of the quotient.
+ *  V           the current comparand, initially divisor*2^(ITER*N-1)
+ *
+ * Cost:
+ *  Current estimate for non-large dividend is
+ *      ceil(log2(quotient) / N) * (10 + 7N/2) + C
+ *  A large dividend is one greater than 2^(31-TOPBITS) and takes a
+ *  different path, as the upper bits of the quotient must be developed
+ *  one bit at a time.
+ */
+
+
+        .globl .rem
+.rem:
+        ! compute sign of result; if neither is negative, no problem
+        orcc    %o1, %o0, %g0   ! either negative?
+        bge     2f                      ! no, go do the divide
+         mov    %o0, %g2        ! compute sign in any case
+
+        tst     %o1
+        bge     1f
+         tst    %o0
+        ! %o1 is definitely negative; %o0 might also be negative
+        bge     2f                      ! if %o0 not negative...
+         sub    %g0, %o1, %o1   ! in any case, make %o1 nonneg
+1:      ! %o0 is negative, %o1 is nonnegative
+        sub     %g0, %o0, %o0   ! make %o0 nonnegative
+2:
+
+        ! Ready to divide.  Compute size of quotient; scale comparand.
+        orcc    %o1, %g0, %o5
+        bne     1f
+         mov    %o0, %o3
+
+                ! Divide by zero trap.  If it returns, return 0 (about as
+                ! wrong as possible, but that is what SunOS does...).
+                ta      ST_DIV0
+                retl
+                 clr    %o0
+
+1:
+        cmp     %o3, %o5                        ! if %o1 exceeds %o0, done
+        blu     Lgot_result             ! (and algorithm fails otherwise)
+         clr    %o2
+
+        sethi   %hi(1 << (32 - 4 - 1)), %g1
+
+        cmp     %o3, %g1
+        blu     Lnot_really_big
+         clr    %o4
+
+        ! Here the dividend is >= 2**(31-N) or so.  We must be careful here,
+        ! as our usual N-at-a-shot divide step will cause overflow and havoc.
+        ! The number of bits in the result here is N*ITER+SC, where SC <= N.
+        ! Compute ITER in an unorthodox manner: know we need to shift V into
+        ! the top decade: so do not even bother to compare to R.
+        1:
+                cmp     %o5, %g1
+                bgeu    3f
+                 mov    1, %g7
+
+                sll     %o5, 4, %o5
+
+                b       1b
+                 add    %o4, 1, %o4
+
+        ! Now compute %g7.
+        2:
+                addcc   %o5, %o5, %o5
+
+                bcc     Lnot_too_big
+                 add    %g7, 1, %g7
+
+                ! We get here if the %o1 overflowed while shifting.
+                ! This means that %o3 has the high-order bit set.
+                ! Restore %o5 and subtract from %o3.
+                sll     %g1, 4, %g1     ! high order bit
+                srl     %o5, 1, %o5             ! rest of %o5
+                add     %o5, %g1, %o5
+
+                b       Ldo_single_div
+                 sub    %g7, 1, %g7
+
+        Lnot_too_big:
+        3:
+                cmp     %o5, %o3
+                blu     2b
+                 nop
+
+                be      Ldo_single_div
+                 nop
+        /* NB: these are commented out in the V8-Sparc manual as well */
+        /* (I do not understand this) */
+        ! %o5 > %o3: went too far: back up 1 step
+        !       srl     %o5, 1, %o5
+        !       dec     %g7
+        ! do single-bit divide steps
+        !
+        ! We have to be careful here.  We know that %o3 >= %o5, so we can do the
+        ! first divide step without thinking.  BUT, the others are conditional,
+        ! and are only done if %o3 >= 0.  Because both %o3 and %o5 may have the high-
+        ! order bit set in the first step, just falling into the regular
+        ! division loop will mess up the first time around.
+        ! So we unroll slightly...
+        Ldo_single_div:
+                subcc   %g7, 1, %g7
+                bl      Lend_regular_divide
+                 nop
+
+                sub     %o3, %o5, %o3
+                mov     1, %o2
+
+                b       Lend_single_divloop
+                 nop
+        Lsingle_divloop:
+                sll     %o2, 1, %o2
+
+                bl      1f
+                 srl    %o5, 1, %o5
+                ! %o3 >= 0
+                sub     %o3, %o5, %o3
+
+                b       2f
+                 add    %o2, 1, %o2
+        1:      ! %o3 < 0
+                add     %o3, %o5, %o3
+                sub     %o2, 1, %o2
+        2:
+        Lend_single_divloop:
+                subcc   %g7, 1, %g7
+                bge     Lsingle_divloop
+                 tst    %o3
+
+                b,a     Lend_regular_divide
+
+Lnot_really_big:
+1:
+        sll     %o5, 4, %o5
+        cmp     %o5, %o3
+        bleu    1b
+         addcc  %o4, 1, %o4
+        be      Lgot_result
+         sub    %o4, 1, %o4
+
+        tst     %o3     ! set up for initial iteration
+Ldivloop:
+        sll     %o2, 4, %o2
+                ! depth 1, accumulated bits 0
+        bl      L.1.16
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+                        ! depth 2, accumulated bits 1
+        bl      L.2.17
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+                        ! depth 3, accumulated bits 3
+        bl      L.3.19
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits 7
+        bl      L.4.23
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+
+        b       9f
+         add    %o2, (7*2+1), %o2
+        
+L.4.23:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (7*2-1), %o2
+        
+L.3.19:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits 5
+        bl      L.4.21
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (5*2+1), %o2
+        
+L.4.21:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (5*2-1), %o2
+        
+L.2.17:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+                        ! depth 3, accumulated bits 1
+        bl      L.3.17
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits 3
+        bl      L.4.19
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (3*2+1), %o2
+
+L.4.19:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (3*2-1), %o2
+
+L.3.17:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits 1
+        bl      L.4.17
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (1*2+1), %o2
+
+L.4.17:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (1*2-1), %o2
+
+L.1.16:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+                        ! depth 2, accumulated bits -1
+        bl      L.2.15
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+                        ! depth 3, accumulated bits -1
+        bl      L.3.15
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits -1
+        bl      L.4.15
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-1*2+1), %o2
+
+L.4.15:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-1*2-1), %o2
+
+L.3.15:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits -3
+        bl      L.4.13
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-3*2+1), %o2
+
+L.4.13:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-3*2-1), %o2
+
+L.2.15:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+                        ! depth 3, accumulated bits -3
+        bl      L.3.13
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits -5
+        bl      L.4.11
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-5*2+1), %o2
+
+L.4.11:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-5*2-1), %o2
+
+
+L.3.13:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+                        ! depth 4, accumulated bits -7
+        bl      L.4.9
+         srl    %o5,1,%o5
+        ! remainder is positive
+        subcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-7*2+1), %o2
+
+L.4.9:
+        ! remainder is negative
+        addcc   %o3,%o5,%o3
+        b       9f
+         add    %o2, (-7*2-1), %o2
+
+        9:
+Lend_regular_divide:
+        subcc   %o4, 1, %o4
+        bge     Ldivloop
+         tst    %o3
+
+        bl,a    Lgot_result
+        ! non-restoring fixup here (one instruction only!)
+        add     %o3, %o1, %o3
+
+Lgot_result:
+        ! check to see if answer should be < 0
+        tst     %g2
+        bl,a    1f
+         sub %g0, %o3, %o3
+1:
+        retl
+         mov %o3, %o0
+
+        .globl  .rem_patch
+.rem_patch:
+        sra     %o0, 0x1f, %o4
+        wr      %o4, 0x0, %y
+        nop
+        nop
+        nop
+        sdivcc  %o0, %o1, %o2
+        bvs,a   1f
+         xnor   %o2, %g0, %o2
+1:      smul    %o2, %o1, %o2
+        retl
+         sub    %o0, %o2, %o0
+        nop