sh: fix seq_file memory leak

When using single_open(), single_release() should be used instead
of seq_release(), otherwise there is a memory leak.

Signed-off-by: Li Zefan <lizf@cn.fujitsu.com>
Signed-off-by: Paul Mundt <lethal@linux-sh.org>

2 files changed, 2 insertions, 2 deletions

diff --git a/arch/sh/mm/cache-debugfs.c b/arch/sh/mm/cache-debugfs.c
index c5b56d52b7d2..0e189ccd4a77 100644
--- a/arch/sh/mm/cache-debugfs.c
+++ b/arch/sh/mm/cache-debugfs.c
@@ -120,7 +120,7 @@ static const struct file_operations cache_debugfs_fops = {
         .open           = cache_debugfs_open,
         .read           = seq_read,
         .llseek         = seq_lseek,
-        .release        = seq_release,
+        .release        = single_release,
 };
 
 static int __init cache_debugfs_init(void)
diff --git a/arch/sh/mm/pmb.c b/arch/sh/mm/pmb.c
index 46911bcbf17b..cef727669c87 100644
--- a/arch/sh/mm/pmb.c
+++ b/arch/sh/mm/pmb.c
@@ -385,7 +385,7 @@ static const struct file_operations pmb_debugfs_fops = {
         .open           = pmb_debugfs_open,
         .read           = seq_read,
         .llseek         = seq_lseek,
-        .release        = seq_release,
+        .release        = single_release,
 };
 
 static int __init pmb_debugfs_init(void)