[IA64] remove redundant display of free swap space in show_mem()

show_mem() has no need to print the amount of free swap space manually because
show_free_areas() does this already and is called by the former.

The two outputs only differ in text formatting:

  printk("Free swap  = %lukB\n", ...);
  printk("Free swap:       %6ldkB\n", ...);

Signed-off-by: Johannes Weiner <hannes@saeurebad.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Tony Luck <tony.luck@intel.com>

1 files changed, 0 insertions, 2 deletions

diff --git a/arch/ia64/mm/contig.c b/arch/ia64/mm/contig.c
index 344f64eca7a9..0479661fa41a 100644
--- a/arch/ia64/mm/contig.c
+++ b/arch/ia64/mm/contig.c
@@ -45,8 +45,6 @@ void show_mem(void)
 
         printk(KERN_INFO "Mem-info:\n");
         show_free_areas();
-        printk(KERN_INFO "Free swap:       %6ldkB\n",
-               nr_swap_pages<<(PAGE_SHIFT-10));
         printk(KERN_INFO "Node memory in pages:\n");
         for_each_online_pgdat(pgdat) {
                 unsigned long present;