timer: Print function name for timer callbacks modifying preemption count

A function scheduled with a timer must not exit with a different
preempt count than it was entered. To make helping users running into
the corresponding BUG() easier also print the name of the bad function
not only its address.

[ tglx: Sanitized printk ]

Signed-off-by: Uwe Kleine-König <u.kleine-koenig@pengutronix.de>
Cc: johnstul@us.ibm.com
Cc: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>

1 files changed, 2 insertions, 5 deletions

diff --git a/kernel/timer.c b/kernel/timer.c
index c61a7949387f..f82f4bfe2d88 100644
--- a/kernel/timer.c
+++ b/kernel/timer.c
@@ -1027,11 +1027,8 @@ static inline void __run_timers(struct tvec_base *base)
                                 lock_map_release(&lockdep_map);
 
                                 if (preempt_count != preempt_count()) {
-                                        printk(KERN_ERR "huh, entered %p "
-                                               "with preempt_count %08x, exited"
-                                               " with %08x?\n",
-                                               fn, preempt_count,
-                                               preempt_count());
+                                        printk(KERN_ERR "timer: %pF preempt leak: %08x -> %08x\n",
+                                               fn, preempt_count, preempt_count());
                                         BUG();
                                 }
                         }